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Diffstat (limited to 'src/examples/longrun.c')
| -rw-r--r-- | src/examples/longrun.c | 90 |
1 files changed, 90 insertions, 0 deletions
diff --git a/src/examples/longrun.c b/src/examples/longrun.c new file mode 100644 index 0000000..19ec9ef --- /dev/null +++ b/src/examples/longrun.c @@ -0,0 +1,90 @@ +/* klaar@ida + + pintos -v -k --fs-disk=2 --qemu -p ../examples/longrun -a longrun -p ../examples/dummy -a dummy -- -f -q run 'longrun 10 50' + + Start a lot of processes and let them finish to test if we + eventually run out of process slots. + + To run the test effectively, if you have a limit on number of + processes, lower the limit to 5 processes and run this test like + + 'longrun 5 400' + + It will fill (and if it works empty) your process table 400 times :-) + + Note that some pintos tests requires at least 16 simultaneous + processes to work, so be sure to increase the limit before running + pintos tests. + */ + +#include <syscall.h> +#include <stdlib.h> +#include <stdio.h> + +#define MAX_SIMULTANEOUS 50 +#define MAX_REPEAT 1000 + +int main(int argc, char* argv[]) +{ + char cmd[15]; + int pid[MAX_SIMULTANEOUS]; + unsigned i = 0; + unsigned j = 0; + unsigned simul = 0; + unsigned repeat = 0; + + if (argc != 3) + { + printf("Usage: %s simultaneous repeat\n" + "Where 'simultaneous' is the number of simultaneous processes to \n" + "start and wait for, and 'repeat' how many times this should be \n" + "repeated.\n", argv[0] + ); + return -1; + } + + simul = atoi(argv[1]); + repeat = atoi(argv[2]); + + if (simul > MAX_SIMULTANEOUS) + { + printf("This test program is compiled with a limitation to max %d \n" + "simultaneos processes.\n", MAX_SIMULTANEOUS); + return -1; + } + + if (repeat > MAX_REPEAT) + { + printf("This test program is compiled with a limitation to max %d \n" + "repetitions.\n", MAX_REPEAT); + return -1; + } + + printf("Will try to start a total of %d processes in groups of %d\n", + simul * repeat, simul); + + for (j = 0; j < repeat; ++j) + { + for (i = 0; i < simul; ++i) + { + snprintf(cmd, 15, "dummy %i", j * simul + i); + pid[i] = exec(cmd); + } + + /* There will never be more than 'simul' processes running + * simultaneously, but in total there will be a lot of processes + * (repeat * simul). Just as you can expect in a real system. + */ + for (i = 0; i < simul; ++i) + { + /* probably nothing left to wait for */ + if (pid[i] == -1) + { + printf("ERROR: Aborting test. Some execution(s) failed\n"); + return j+1; + } + wait(pid[i]); + } + } + return 0; +} |
